已知数列{an}的通项公式an=log3(n∈N+),设其前n项和为Sn,则使Sn<

已知数列{an}的通项公式anlog3(n∈N),设其前n项和为Sn,则使Sn<4成立的最小自然数n等于(  )

(A)83  (B)82  (C)81  (D)80

答案

C.Snlog31log32log32log33+…+log3nlog3(n1)

log3(n1)<4,解得n>34180.最小自然数为81.

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