将质量为m的小球从桌角边竖直向上抛出,小球能达到的最大高度离地

将质量为m的小球从桌角边竖直向上抛出,小球能达到的最大高度离地面H,桌面离地面高为h.若以桌面为重力势能的参考平面,不计空气阻力,则小球落地时的机械能为(    )

A.mgH            B.mgh            C.mg(h+H)          D.mg(H-h)

答案

解析:不计空气阻力,小球的机械能守恒,整个运动过程中,机械能处处相等.落地点的机械能等于最高点的机械能.在最高点,小球的速度为零,动能为零,小球距桌面高度为H-h,所以小球的重力势能为mg(H-h),落地点小球的机械能也为mg(H-h).

答案:D

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