某溶液中含有HCO3-、SO32-、SiO32-、Cl-等四种离子,若向其中加入

某溶液中含有HCO3、SO32、SiO32、Cl等四种离子,若向其中加入某种试剂后,发现溶液中

仅有HCO3、SO32两种离子数量大量减少。则加入的试剂可能是   (    )

    A.盐酸          B.过氧化钠       C.双氧水        D.氯化钡溶液

答案

B


解析:

因为SiO32没有减少,所以不可能是盐酸和氯化钡,双氧水只能使SO32减少,过氧化钠溶于水既有碱性又有氧化性,HCO3、SO32两种离子数量均大量减少。

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