设函数f(x)=的反函数f-1(x),且f-1()=a,则f(a+7)=(    )A.-2         

设函数f(x)=的反函数f-1(x),且f-1()=a,则f(a+7)=(    )

A.-2             B.-1           C.1            D.2

答案

答案:

A  【解析】本题考查分段函数及反函数知识;据题意由f-1()=a即f(a)=,由分段函数解析式知只能2a-4=a=1,故f(a+7)=f(8)=-log39=-2.

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