有A、B、C、D、E、F六种化合物,它们之间的反应关系如下所示: ①A+

ABCDEF六种化合物,它们之间的反应关系如下所示:

A+BC+E                  C+NaOH→蓝色沉淀D+F    

 


DA+E                    F+BaNO32 →白色沉淀+NaNO3

回答下列问题:

 ⑴写出它们的化学式:A          B              C           

 

 

D           E              F               

   写出①②④的离子反应方程式:

                                                         

                                                       

                                                         

答案

 

    出它们的化学式:(各1分)A   CuO      B   H2SO4     C   CuSO4

    D   CuOHE  H2O     F     Na2SO4

   写出①②④的离子反应方程式:(各3分)

    CuO+2H+=Cu2++H2O                                                     

    Cu2++2OH-=CuOH2                                                    

 

     Ba2++SO42-=BaSO4                                            

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