设数列{an}满足a1=1,且an+1-an=n+1(n∈N*), 则数列的前10项和为 .
【解析】因为an=(an-an-1)+(an-1-an-2)+…+(a2-a1)+a1=n+(n-1)+…+2+1 =,
所以==2,
所以 =2++…+=.