如图4­2­43(1),在△ABC中,AB=AC,点D是BC的中点,点E在AD上. (1)求

如图4­2­43(1),在△ABC中,ABAC,点DBC的中点,点EAD上.

(1)求证:BECE

(2)BE的延长线交AC于点F,且BFAC,垂足为F,如图4­2­43(2),∠BAC45°,原题设其他条件不变.求证:△AEF≌△BCF.

   

答案

证明:(1)ABACDBC的中点,

∴∠BAE=∠CAE.

在△ABE和△ACE中,ABAC,∠BAE=∠CAEAEAE

∴△ABE≌△ACE(SAS)

BECE.

(2)∵∠BAC45°BFAF

∴△ABF为等腰直角三角形.∴AFBF.

(1)ADBC,∴∠EAF=∠CBF.

在△AEF和△BCF中,AFBF,∠AFE=∠BFC90°,∠EAF=∠CBF

∴△AEF≌△BCF.

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