已知f(x)=asinx + btanx+2，且满足f()=7,求f()的值．

已知f(x)=asinx + btanx+2，且满足f()=7,求f()的值．



答案

解:∵f()=asin+btan+2=7, ∴f(-)=-asin-btan+2=-3. ∵f(x+2π)=f(x),∴f()=f(40π-)=f(-)=-3.

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已知f(x)=asinx + btanx+2，且满足f()=7,求f()的值．

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