先化简,再求值:
x2 + (-x2 +3xy +2y2)-(x2-xy +2y2),其中x=1,y=3.
x2 + (-x2 +3xy +2y2)-(x2-xy +2y2)
= x2-x2 +3xy +2y2-x2+xy-2y2 = 4xy-x2
当x=1,y=3时 4xy-x2=4×1×3-1=11。