下列各组离子在指定的溶液中能大量共存的是() ①无色溶液中:K+

下列各组离子在指定的溶液中能大量共存的是()

无色溶液中:K+Cu2+Na+SO42

②pH11的溶液中:CO32Na+AlO2NO3

加入Al能放出H2的溶液中:ClHCO3NO3NH4+

在由水电离出的cOH)=1013 mol·L1的溶液中:Na+Ba2+ClI

能使红色石蕊试纸变为蓝色的溶液:Na+ClS2ClO

强酸性溶液中:Fe2+Al3+NO3Cl

A①②⑤          B②④⑥           C②④         D③⑤⑥

答案

【答案解析】C   解析:无色溶液中不存在有色离子,Cu2+为有色离子,在溶液中不能大量共存,故错误;
②pH=11
的溶液中存在大量氢氧根离子,CO32-Na+AlO2-NO3-离子之间不反应,且都不与氢氧根离子反应,在溶液中能够大量共存,故正确;
加入Al能放出H2的溶液中存在大量H+OH-HCO3-NH4+离子与氢氧根离子反应,HCO3-与氢离子反应,在溶液中不能够大量共存,故错误;
在由水电离出的cOH-=10-13mol•L-1的溶液中存在大量H+OH-Na+Ba2+Cl-I-离子之间不反应,且都不与H+OH-反应,在溶液中能够大量共存,故正确;
能使红色石蕊试纸变为蓝色的溶液中存在大量OH-S2-ClO-离子之间发生氧化还原反应,在溶液中不能大量共存,故错误;
酸性溶液中NO3-具有强氧化性,能够氧化Fe2+,在溶液中不能大量共存,故错误;

故答案选C

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