连掷两次骰子分别得到点数m、n,则向量a=(m,n)与向量b=(-1,1)的

连掷两次骰子分别得到点数mn,则向量a(mn)与向量b(1,1)的夹角θ>90°的概率是(  )

(A)  (B)  (C)  (D)

答案

A.a(mn)b(1,1),若夹角θ>90°,则a·b=-mn<0,∴m>n.

基本事件总共有6×636(),符合要求的有(2,1)(3,1)(3,2)(4,1)(4,2)(4,3)(5,1),…,(5,4)(6,1),…,(6,5),共1234515().

P.

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