函数(a≠0)与y=a(x﹣1)(a≠0)在同一坐标系中的大致图象是(

函数a0)与y=ax1)(a0)在同一坐标系中的大致图象是(  )

A  B  C  D

答案

A【考点】反比例函数的图象;一次函数的图象.

【分析】首先把一次函数化为y=axa,再分情况进行讨论,a0时;a0时,分别讨论出两函数所在象限,即可选出答案.

【解答】解:y=ax1=axa

a0时,反比例函数在第一、三象限,一次函数在第一、三、四象限,

a0时,反比例函数在第二、四象限,一次函数在第一、二、四象限,

故选:A

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