已知函数. (Ⅰ)求f(x)的最大值及最小正周期; (Ⅱ)求使f(x)≥2的x的取

已知函数.

(Ⅰ)f(x)的最大值及最小正周期;

(Ⅱ)求使f(x)≥2x的取值范围

答案

解:(Ⅰ)∵f(x)=sin(2x+)+sin(2x-)+2cos2x

               =sin2xcos+cos2xsin+sin2xcos-cos2xsin+cos2x+1

               =sin2x+cos2x+1

               = 2sin(2x+)+1

         f(x)max=2+1=3

          

(Ⅱ)∵f(x)2

       2sin(2x+)+12

      sin(2x+)

      2kx+2x+2k+

         kxk+(kZ)

      ∴使f(x) 2x的取值范围是{x|kxk+,kZ}

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