已知y1=x,y2=
,y3=
,y4=
,…,则y1·y2014=( )
A.2x2 B.1 C.2 D.
已知y1=x,y2=
,y3=
,y4=
,…,则y1·y2014=( )
A.2x2 B.1 C.2 D.
C.∵y1=x,∴y2=
=
=
=
,∴y3=
=2÷
=2×
=
=
=
x,因此,y1,y2,
…,y2014的值分别为
x,
,…,每两
个数一循环,则y2014=
,∴y1·y2014=
x·
=2.