A.a1=a2,t1=t2 B.a1>a2,t1>t2 C.a1>a2,t1<t2 D.a1<a2,t1<t2
解析:上升阶段,空气阻力F与重力同向,设加速度为a1,则a1=>g;下降阶段,空气阻力与重力方向相反,设加速度为a2,则a2=<g,故a1>a2.另据h=at2,t=,可判定t1<t2,故正确选项为C.
答案:C