(1)求BC边的长;
(2)若点D是AB的中点,求中线CD的长度.
解:(1)由cosC=得sinC=,
sinA=sin(180°-45°-C)
=(cosC+sinC)
=.
由正弦定理知BC=·sinA=.
(2)AB=·sinC==2.
BD=AB=1.
由余弦定理知CD=.