电解饱和食盐水，当阴极附近有0.8 mol氢氧化钠生成时，导线中通过

电解饱和食盐水，当阴极附近有0.8 mol氢氧化钠生成时，导线中通过的电子的物质的量是（）

A．0.16 mol B．0.2 mol C．0.4 mol D．0.8 mol

答案

【答案】D

【解析】由H₂OH^＋＋OH^－知每有1 mol H^＋放电，就会生成1 mol OH^－，而1 mol H^＋放电需要转移1 mol e^－，故有0.8 mol NaOH生成，导线中就有0.8 mol e^－通过。

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