利用高楼楼顶下垂的单摆、实验室用的刻度尺和秒表,如何测定当地

利用高楼楼顶下垂的单摆、实验室用的刻度尺和秒表,如何测定当地的重力加速度?请你设计一种行之有效的方法,写出简要的实验原理及计算g值的公式.(注意:单摆摆长无法直接测出)

答案


解析:

设摆长为l,让其摆动,设法测出其周期T1,然后用打结的办法将原摆长缩短Δl(Δl≤1 m)并用刻度尺测出Δl,同样让其摆动并设法测出周期T2,则由单摆的周期公式T=2π可得:T1=2π                           ①

T2=                                       ②

联解①②两式可得重力加速度的最后计算为:

g=.

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