已知f(x)=lg,A=f(x+1),B=f(x)+f(1),比较A、B的大小.

已知f(x)=lg,A=f(x+1),B=f(x)+f(1),比较A、B的大小.

答案

思路分析:比较大小通过作差与0比较.

解:A=f(x+1)

=lg,

B=lg.

=(10x-10-x),

∴当x=0时,A=B;当x>0时,A>B;当x<0时,A<B.

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