已知f(x)=lg,A=f(x+1),B=f(x)+f(1)，比较A、B的大小.

答案

思路分析：比较大小通过作差与0比较.

解：A=f(x+1)

=lg,

B=lg.

∵=(10^x-10^-x)，

∴当x=0时，A=B；当x＞0时，A＞B;当x＜0时，A＜B.

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已知f(x)=lg,A=f(x+1),B=f(x)+f(1)，比较A、B的大小.

答案

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