方程x2+(m-1)x+m2-2=0的两个根一个小于-1,另一个大于1,那么实数m的取

方程x2+(m-1)x+m2-2=0的两个根一个小于-1,另一个大于1,那么实数m的取值范围是……

(  )

A.(-, )

B.(-2,0)

C.(-2,1)

D.(0,1)

答案

解析

:设f(x)=x2+(m-1)x+m2-2,

由条件可知

∴0<m<1.

答案

:D

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