若函数f(x)=2sin(-2<x<10)的图象与x轴交于点A,过点A的直线l与函数的

若函f(x)=2sin(-2<x<10)的图象与x轴交于点A,过点A的直线l与函数的图象交于B,C两点,(+)·=(  )

A.-32           B.-16           C.16            D.32

答案

D.f(x)=0,解得x=4,A(4,0),过点A的直线l与函数的图象交于B,C两点,根据对称性可知,ABC的中点,所以+=2,所以(+)·=2·=2||2=2×42=32.

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