如图所示,虚线为某一带电粒子只在电场力作用下的运动轨迹,  M

如图所示,虚线为某一带电粒子只在电场力作用下的运动轨迹,  MN为运动轨迹上两点,下列说法中正确的是

   A.如果实线表示电场线,则该粒子在M点的动能一定小于在N点的动能

   B.如果实线表示等势面,则该粒子在M点的动能一定小于在N 点的动能

   C.不论实线表示电场线还是等势面,粒子在M点的加速度 一定小于在N点的加速度

   D.不论实线表示电场线还是等势面,都不能确定MN 两点电势高低关系,但能确定该粒子所带电荷的正负

答案

AC

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