已知向量a=,b=(x,1),其中x>0,若(a-2b)∥(2a+b),则实数x= .

已知向量a=b=(x1),其中x>0,若(a-2b)(2a+b),则实数x=    .

答案

.4 【解析】由题意得a-2b=2a+b=(16+xx+1),因为(a-2b)(2a+b),所以(8-2x)(x+1)=(16+x),整理得x2=16,又因为x>0,所以x=4.

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