求数列,,,,…的通项公式,并求其前n项和.

求数列,…的通项公式,并求其前n项和.

答案

an=n+.

  Sn=(1+)+(2+)+(3+)+…+(n+

  =(1+2+3+…+n)+(+++…+

  =+=+1-.


解析:

   拆项法是求特殊数列前n项和的常用方法,遇到数列的项之间的规律不明显时,可考虑采用拆项法,从而找到各项之间的规律,求出通项公式. 乍一看似乎数列的各项之间没有什么规律可循,将题中各项变形可得=1+=2+=3+=4+.

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