已知k1<0<k2,则函数y=k1x-1和y=的图象大致是( )

已知k10k2,则函数yk1x1y的图象大致是(  )

答案

A 【解析】∵k20,∴反比例函数的图象在第一、三象限,∵k10,函数yk1x1y轴的交点为(0,-1),∴一次函数图象经过二、三、四象限,故选A.

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