交流发电机矩形线圈边长ab=cd=0.4 m,bc=ad=0.2 m,共50匝,线圈电

交流发电机矩形线圈边长ab=cd=0.4 m,bc=ad=0.2 m,共50匝,线圈电阻r=1 Ω,线圈在B=0.2 T的匀强磁场中,绕垂直磁场方向的轴OO′以 r/s转速匀速转动,外接电阻9 Ω,如图3-2-18所示.求:

3-2-18

(1)电压表读数;

(2)电阻R上电功率.

答案

解析:(1)线圈在磁场中产生:

=NBSω

=50×0.2×0.4×0.2××2 π

=160 V

I=

U=IR=72≈101.5 V

(2)P=UI=72×8=1152 W

答案:(1)101.5 V (2)1152 W

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