阿伏加德罗常数的值约为6.02×1023mol-1,下列叙述中正确的是A.2molSO

阿伏加德罗常数的值约为6.02×1023mol1,下列叙述中正确的是

A.2molSO2和1mol O2混合在V2O5存在的条件下于密闭容器中加热反应后,容器内物质分子数等于2×6.02×1023

B.电解精炼铜时转移了6.02×1023个电子,阴极析出32 g铜

C.2.9g 2CaSO4·H2O含有的结晶水分子数为0.02×6.02×1023 (2CaSO4·H2O式量为290)

D.含0.2mol H2SO4的浓硫酸与足量铜反应,生成SO2的分子数为0.1×6.02×1023

 

答案

B

解析:

 

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