在等差数列{an}中，a1+a5=16，则a3等于（ ）                 �

在等差数列{a_n}中，a₁+a₅=16，则a₃等于（　　）                                                  

A．8                                  B．4                                  C．﹣4                              D．﹣8

A【分析】利用等差数列的性质2a₃=a₁+a₅，根据已知中等差数列{a_n}中，a₁+a₅=16，代入即可得到a₃的值．                   

【解答】解：∵数列{a_n}为等差数列                                                                      

∴2a₃=a₁+a₅=16，                                                                                                

∴a₃=8                                                                                                                

故选A                                                                                                                

【点评】本题考查的知识点是等差数列的性质，其中等差数列最重要的性质：当m+n=p+q时，a_m+a_n=a_p+a_q，是解答本题的关键．