二元一次方程组的解满足2x-ky=10,则k的值等于(    ) A.-3      

二元一次方程组的解满足2x-ky=10,k的值等于(   

A.-3                 B.2              C.4                 D.5

答案

解析:先解方程组然后把求得的解代入2x-ky=10,就可求出k的值.解方程组代入2x-ky=10,2+2k=10,解得k=4.

答案:C

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