若sin α+cos α=
(0<α<π),则tan α=( )
A.-
B.
C.-
D.![]()
若sin α+cos α=
(0<α<π),则tan α=( )
A.-
B.
C.-
D.![]()
C
[解析] 由sin α+cos α=
(0<α<π)两边平方,得1+sin 2α=
,sin 2α=-
,又sin 2α=
=-
,60tan2α+169tan α+60=0,
∴tan α=-
或tan α=-
,
又sin α+cos α>0,∴|sin α|>|cos α|,
即|tan α|>1,故tan α=-
,故选C.