如图所示,两平行金属板竖直放置,A、B两小孔正好相对,两板间电

如图所示,两平行金属板竖直放置,AB两小孔正好相对,两板间电压为500V,能量为400eV的电子,从A孔沿垂直于板面方向射入电场,经过一段时间,电子将离开电场,电子离开电场时的能量为

   

A900eV      B500eV

C400eV      D100eV

答案

C

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