下列排列顺序,错误的是  A.原子半径:O<S<Na B.稳定性:PH3>H

下列排列顺序,错误的是 

A.原子半径:O<S<Na

B.稳定性:PH3>H2S>NH3

C.酸性:H3PO4<H2SO4<HClO4

D.碱性:Al(OH)3<Mg(OH)2<NaOH

答案


解析:

比较的依据是,同主族元素从上到下电子层数增加,原子半径加大,氧和硫都在ⅥA族,氧在第2周期,硫在第3周期,原子半径S>O,钠和硫都在第3周期,同周期元素从左到右原子半径逐渐减小,故原子半径Na>S,题干要求错误项,排除A。周期元素氢化物从左到右稳定性增强,故稳定性H2S>PH3,同主族元素氢化物从上到下减弱,故NH3>PH3,B错。同周期元素从左到右,其最高价氧化物对应水化合物的酸性逐渐增强,碱性逐渐减弱,C和D都对,选项排除C和D。

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