A.y=-2x B.y=
x C.y=
x D.y=2x
A.y=-2x B.y=
x C.y=
x D.y=2x
(文)设切线方程为y=kx,即kx-y=0.
又x2+y2-2x+4y=0,得(x-1)2+(y+2)2=5,
圆心为(1,-2),半径为
.
∴
.
解得4k2-4k+1=0,k=
.
∴切线方程为y=
x.故选C.
答案:
C