(6分)一只灯泡接到220V的家庭电路中,10min消耗的电能是2.4×104J,

(6分)一只灯泡接到220V的家庭电路中,10min消耗的电能是2.4×104J,求:

(1)灯泡的电功率是多大?

(2)灯泡中通过的电流是多大?

(3)灯丝的电阻是多大?

 

答案

(1)40W  (2)0.18A    (3)1210Ω

解析:(1)根据公式P=W/t=2.4×104J/600S=40W

(2)I=P/U=40W/220V=0.18A

(3)R=U2/P=(22OV)2/40W=1210Ω

:]

 

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