(1)CH2=CH2
CH3CH2CH2CH3
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(1)CH2=CH2
CH3CH2CH2CH3
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解析:(1)二碳变四碳,碳链增长,可通过二元卤代烃的氰基取代而完成。路线为:

(2)七碳变六碳,环状结构被保留,可通过碱石灰脱羧完成:

答案:(1)CH2=CH2+Br2
CH2BrCH2Br
CH2BrCH2Br+2NaCN
CH2CNCH2CN+2NaBr
CH2CNCH2CN
HOOCCH2CH2COOH
HOOCCH2CH2COOH
HOCH2CH2CH2CH2OH
HOCH2CH2CH2CH2OH
CH2=CH—CH=CH2+2H2O
CH2=CH—CH=CH2+2H2O
CH3CH2CH2CH3
(2)![]()
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