已知双曲线的中心在原点,焦点F1,F2在坐标轴上,离心率为,且过

已知双曲线的中心在原点,焦点F1F2在坐标轴上,离心率为,且过点(4,-)

(1)求双曲线方程;

(2)若点M(3m)在双曲线上,求证:·0

(3)F1MF2的面积.

答案

[分析] 由离心率为可看出它是等轴双曲线;从此隐含条件入手,可使运算变得简单.

[解析] (1)e可设双曲线方程为x2y2λ(λ0)

(4,-)点,1610λ,即λ6

双曲线方程为x2y26.

(2)证法1:由(1)可知,双曲线中ab

c2F1(20)F2(20)

(3m)在双曲线上,9m26m23.

kMF1·kMF2=-1.·0.

证法2(32,-m)(23,-m)

·(32)×(32)m2=-3m2

M点在双曲线上,9m26,即m230

·0.

(3)F1MF2的底|F1F2|4

F1MF2的高h|m|SF1MF26.

[点评] 双曲线的标准方程和几何性质中涉及很多基本量,如abce等,树立基本量思想对于确定双曲线方程和认识其几何性质有很大帮助.

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