质量为M的物块以速度V运动,与质量为m的静止物块发生正撞,碰撞后

质量为M的物块以速度V运动,与质量为m的静止物块发生正撞,碰撞后两者的动量正好相等,两者质量之比M/m可能为

A.2        B.3         C.4        D. 5

答案

【答案】AB

【解析】碰后动量相等,设此动量为P,方向一定与V相同,则碰后速度关系可知,碰后m的速度v2一定要大小或等于碰后M的速度v1v2v1mv2=Mv1,可知,由能量关系可知:,解得:,由上述结论可知,AB项正确。

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