下列叙述正确的是 A. Fe分别与氯气和稀盐酸反应所得氯化物相同 B.K

下列叙述正确的是

A. Fe分别与氯气和稀盐酸反应所得氯化物相同

B.KZn分别与不足量的稀硫酸反应所得溶液均呈中性

C. LiNaK的原子半价和密度随原子序数的增加而增大

D.CPSCl的最高价氧化物对应水化物的酸性逐渐增强

答案

【解析】铁属于变价属于变价金属,与强氧化剂反应生成Fe3,与弱氧化剂反应生成Fe2,氯气属于强氧化剂,盐酸属于非氧化性酸,因此选项A不正确;当硫酸不足时,ZnK均过量,但过量的K会继续和水反应生成KOH而呈碱性,B不正确;同主族元素自上而下,随着核电荷数的增加电子层数逐渐增多,原子半径逐渐增大,密度也逐渐增大,但Na的密度大于K的,C不正确;CPSCl的非金属性逐渐增强,所以其最高价氧化物对应水化物的酸性逐渐增强,D正确。

【答案】D

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