正常情况下，人体摄人和排出的无机盐是保持平衡的．若只饮

正常情况下，人体摄人和排出的无机盐是保持平衡的．若只饮水不进食，则（）

A．K^＋排出量大于正常情况下的排出量

B．K^＋排出量等于正常情况下的排出量

C．K^＋排出量小于正常情况下的排出量

D．K^＋排出量等于零

答案

解析:

K^＋的排出途径是经肾脏随尿排出，其排出特点是多吃多排，少吃少排，不吃也排．只饮水不进食的人，K^＋的排出量少于正常情况下的排出量．

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正常情况下，人体摄人和排出的无机盐是保持平衡的．若只饮

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