(6分)质量m=2×103kg,汽车以的速度通过某凸形桥的最高点时,受到

(6分)质量m=2×103kg,汽车以的速度通过某凸形桥的最高点时,受到桥面的支持力N=1.5×104N,取g=10m/s2,则桥面的曲率半径为多少?当车速为多大时,车在桥最高点时对桥面的压力恰好为零?

答案

(6分)解:桥面的曲率半径为r,由向心力公式可知

                                                   (1分)

                                              (1分)

代入数据解得  m                                          (1分)

车在桥最高点时对桥面的压力恰好为零时有              (2分)

代入数据解得  =20 m/s                                         (1分)

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