如图7-2-6所示,为用一直流电动机提升重物的装置,重物质量m为50kg

如图7-2-6所示,为用一直流电动机提升重物的装置,重物质量m为50kg,恒定电压 U=110V,不计摩擦.当电动机以0.85m/s恒定速度向上提升重物时,电路中的电流强度I=5A,由此可知电动机线圈的电阻R=       Ω.(g=10m/s2

答案

R=5Ω


解析:

该题是直流电路中能量的转化和守恒问题,总能量是电源做功,电源转化的电能,全部输入给电动机,电动机属非纯电阻电路;输给电动机的电能,其中一部分用于提升重物转化为机械能,另一部分消耗在电动机线圈的电阻上,转化为内能.

电源的功率为PUI

对电动机由能量守恒,PPPR

PmgvPRI2R,则UImgvI2R,得R=5Ω

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