解:∵A={x|sinx=},
∴A={x|x=2kπ+或x=2kπ+,k∈Z
∵B={x|tanx=},∴B={x|x=kπ+,k∈Z
={x|x=2kπ+或x=2kπ+,k∈Z
∴A∩B={x|x=2kπ+,k∈Z