已知下面各数列{an}的前n项和Sn的公式,求{an}的通项公式.

已知下面各数列{an}的前n项和Sn的公式,求{an}的通项公式.

答案

(1)Sn=2n2-3n;(2)Sn=3n-2.

解析:(1)当n≥2时,an=Sn-Sn-1=2n2-3n-[2(n-1)2-3(n-1)]=4n-5.

当n=1时,a1=S1=-1满足上式,

∴an=4n-5.

(2)当n≥2时,an=Sn-Sn-1=(3n-2)-(3n-1-2)=2×3n-1,

当n=1时,a1=S1=3-2=1,

∴an=

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