A.[(b-c)/125a]×100% B.[(b-2c)/125a]×100%
C.[(b-c)/250a]×100% D.[(8b-8c)/a]×100%
A.[(b-c)/125a]×100% B.[(b-2c)/125a]×100%
C.[(b-c)/250a]×100% D.[(8b-8c)/a]×100%
解析:NaOH、Ba(OH)2恰好与H2SO4反应,有关系式n(NaOH)+2n〔Ba(OH)2〕=2n(H2SO4),设NaOH纯度为x%,故有+c×10-3×0.1×2=b×10-3×0.1×2。纯度x%=
×100%