在△ABC中,角A,B,C所对的边分别为a,b,c,满足
,D是BC边上的一点. (Ⅰ) 求角B的大小;
(Ⅱ) 若AC=7,AD=5,DC=3,求AB的长.

在△ABC中,角A,B,C所对的边分别为a,b,c,满足
,D是BC边上的一点. (Ⅰ) 求角B的大小;
(Ⅱ) 若AC=7,AD=5,DC=3,求AB的长.

(Ⅰ) 由
,
得
,即
,
根据正弦定理,
,·········· 4分
所以
,又
,
所以
.····································································································· 6分
(Ⅱ) 在△ADC中,AC=7,AD=5,DC=3,
由余弦定理得![]()
,
所以
ADC=120°,
ADB=60°,········································································ 9分
在△ABD中,AD=5,
B=45°,
ADB=60°,
由正弦定理,得
,
所以AB=
.·············································· 12分