已知反应:①Cu+2H2SO4(浓)SO2↑+2H2O+CuSO4;②Cu+4HNO3(浓)====Cu(NO3)2+ 2NO2↑+2H

已知反应:①Cu+2H2SO4(浓)SO2↑+2H2O+CuSO4;②Cu+4HNO3(浓)====Cu(NO3)2+

2NO2↑+2H2O(剧烈);③3Cu+8HNO3(稀)====3Cu(NO3)2+2NO↑+4H2O(较慢),由此可知下列四种物质的氧化性由强到弱的顺序为__________。(填字母)

A.浓H2SO4           B.稀H2SO4          C.浓HNO3            D.稀HNO3

答案

CDBA


解析:

根据反应条件越易,现象越剧烈,氧化剂的氧化性(氧化同一种还原剂)越强,可知浓HNO3、稀HNO3、浓H2SO4的氧化性逐渐减弱,而Cu与稀H2SO4不反应,其氧化性最弱。

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