如图,点B、F、C、E在一条直线上,BC=EF,AB∥ED,AC∥FD,求证:AC=DF.
证明:∵FB=CE,
∴FB+FC=CE+FC,
∴BC=EF,
∵AB∥ED,AC∥FD,
∴∠B=∠E,∠ACB=∠DFE,
∵在△ABC和△DEF中,
,
∴△ABC≌△DEF(ASA),
∴AC=DF.