某同学在做“用单摆测重力加速度”实验中,先测得摆线长为97.50 cm

某同学在做“用单摆测重力加速度”实验中,先测得摆线长为97.50 cm,摆球直径2.00 cm,然后用停表记录了单摆振动50次所用的时间如下图所示,则

(1)该摆摆长为___________cm,停表表示读数为___________s.

(2)如果测得的g值偏小,可能的原因是(    )

A.测摆线时摆线拉得过紧

B.摆线上端悬点未固定,振动中出现松动,使摆线长度增加了

C.开始计时时,停表过迟按下

D.实验时误将49次全振动数为50次

 

答案

(1)98.5  , 99.8   (2)  B

解析:略

 

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