已知同温度下的溶解度:Zn(OH)2>ZnS,MgCO3>Mg(OH)2;就溶解或电离出

已知同温度下的溶解度:Zn(OH)2>ZnSMgCO3>Mg(OH)2;就溶解或电离出S2的能力而言,FeS>H2S>CuS,则下列离子方程式错误的是                         (   )

AMg22HCO32Ca24OH===Mg(OH)2↓+2CaCO3↓+2H2O

BCu2H2S===CuS↓+2H

CZn2S22H2O===Zn(OH)2↓+H2S

DFeS2H===Fe2H2S

答案

C

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