马铃薯块茎进行无氧呼吸,叶肉细胞进行有氧呼吸。若它们共产生了

马铃薯块茎进行无氧呼吸,叶肉细胞进行有氧呼吸。若它们共产生了18 mol 的CO2,且两种呼吸作用转移到ATP中的能量相等,则它们共分解了多少摩尔的葡萄糖(  )

A.35 

B.42

C.24 

D.60

 

答案

D

马铃薯块茎进行无氧呼吸分解1 mol葡萄糖只产生2 mol乳酸,释放的能量产生2 mol ATP。有氧呼吸时,分解1 molC6H12O6释放6 mol CO2,产生38 mol ATP。现呼吸产生18 mol的CO2,全为叶肉细胞有氧呼吸形成的,共分解了3 mol C6H12O6,产生114 mol的ATP。无氧呼吸要产生114 mol的ATP,必须分解57 mol的C6H12O6,所以共分解了60 mol的C6H12O6。

 

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